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Distance from Drobeta-Turnu Severin to Belgrade

Straight line

174 km
108 mi · 94 NM

By road

253 km
157 mi

Travel time

4 h 4 min
flight ≈ 43 min

Direction

W 277°
initial bearing

Open in the calculator (stops, directions, fuel cost) → Belgrade → Drobeta-Turnu Severin

How far is Drobeta-Turnu Severin from Belgrade?

Drobeta-Turnu Severin (Romania) and Belgrade (Serbia) are a medium distance apart: 174 km in a straight line, that is 108 miles or 94 nautical miles. The distance is measured over the Earth's surface (WGS84 ellipsoid) along the shortest possible path.

By road, Drobeta-Turnu Severin to Belgrade is 253 km (157 miles), about 4 h 4 min by car on the fastest route, without traffic or stops. The road is 45% longer than the straight line.

From Drobeta-Turnu Severin, Belgrade lies to the west (initial bearing 277°). The route crosses from Romania into Serbia. The halfway point is at 44.7207°, 21.5607°.

A direct flight would take about 43 min (800 km/h cruise plus take-off and landing). The road distance and driving time are calculated on the map from OpenStreetMap roads.

Frequently asked questions

How far is Drobeta-Turnu Severin from Belgrade?

By road it is 253 km (157 miles) from Drobeta-Turnu Severin to Belgrade; in a straight line it is 174 km (108 miles).

How long is the drive from Drobeta-Turnu Severin to Belgrade?

About 4 h 4 min on the fastest route (253 km), without traffic or stops.

In which direction is Belgrade from Drobeta-Turnu Severin?

Belgrade is to the west of Drobeta-Turnu Severin, at an initial bearing of 277°.

How long is the flight from Drobeta-Turnu Severin to Belgrade?

A direct flight would take about 43 min at an average cruising speed of 800 km/h.

How is the distance calculated?

The straight-line distance is computed on the WGS84 ellipsoid with the Vincenty formula, accurate to the metre. The road distance comes from OpenStreetMap roads.