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Distance from Belgrade to Drobeta-Turnu Severin

Straight line

174 km
108 mi · 94 NM

By road

253 km
157 mi

Travel time

4 h 5 min
flight ≈ 43 min

Direction

E 96°
initial bearing

Open in the calculator (stops, directions, fuel cost) → Drobeta-Turnu Severin → Belgrade

How far is Belgrade from Drobeta-Turnu Severin?

Belgrade (Serbia) and Drobeta-Turnu Severin (Romania) are a medium distance apart: 174 km in a straight line, that is 108 miles or 94 nautical miles. The distance is measured over the Earth's surface (WGS84 ellipsoid) along the shortest possible path.

By road, Belgrade to Drobeta-Turnu Severin is 253 km (157 miles), about 4 h 5 min by car on the fastest route, without traffic or stops. The road is 45% longer than the straight line.

From Belgrade, Drobeta-Turnu Severin lies to the east (initial bearing 96°). The route crosses from Serbia into Romania. The halfway point is at 44.7207°, 21.5607°.

A direct flight would take about 43 min (800 km/h cruise plus take-off and landing). The road distance and driving time are calculated on the map from OpenStreetMap roads.

Frequently asked questions

How far is Belgrade from Drobeta-Turnu Severin?

By road it is 253 km (157 miles) from Belgrade to Drobeta-Turnu Severin; in a straight line it is 174 km (108 miles).

How long is the drive from Belgrade to Drobeta-Turnu Severin?

About 4 h 5 min on the fastest route (253 km), without traffic or stops.

In which direction is Drobeta-Turnu Severin from Belgrade?

Drobeta-Turnu Severin is to the east of Belgrade, at an initial bearing of 96°.

How long is the flight from Belgrade to Drobeta-Turnu Severin?

A direct flight would take about 43 min at an average cruising speed of 800 km/h.

How is the distance calculated?

The straight-line distance is computed on the WGS84 ellipsoid with the Vincenty formula, accurate to the metre. The road distance comes from OpenStreetMap roads.