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Distance from Belgrade to Lugoj

Straight line

150 km
93 mi · 81 NM

By road

220 km
137 mi

Travel time

3 h 35 min
flight ≈ 41 min

Direction

NE 48°
initial bearing

Open in the calculator (stops, directions, fuel cost) → Lugoj → Belgrade

How far is Belgrade from Lugoj?

Belgrade (Serbia) and Lugoj (Romania) are a short distance apart: 150 km in a straight line, that is 93 miles or 81 nautical miles. The distance is measured over the Earth's surface (WGS84 ellipsoid) along the shortest possible path.

By road, Belgrade to Lugoj is 220 km (137 miles), about 3 h 35 min by car on the fastest route, without traffic or stops. The road is 47% longer than the straight line.

From Belgrade, Lugoj lies to the north-east (initial bearing 48°). The route crosses from Serbia into Romania. The halfway point is at 45.2486°, 21.1785°.

A direct flight would take about 41 min (800 km/h cruise plus take-off and landing). The road distance and driving time are calculated on the map from OpenStreetMap roads.

Frequently asked questions

How far is Belgrade from Lugoj?

By road it is 220 km (137 miles) from Belgrade to Lugoj; in a straight line it is 150 km (93 miles).

How long is the drive from Belgrade to Lugoj?

About 3 h 35 min on the fastest route (220 km), without traffic or stops.

In which direction is Lugoj from Belgrade?

Lugoj is to the north-east of Belgrade, at an initial bearing of 48°.

How long is the flight from Belgrade to Lugoj?

A direct flight would take about 41 min at an average cruising speed of 800 km/h.

How is the distance calculated?

The straight-line distance is computed on the WGS84 ellipsoid with the Vincenty formula, accurate to the metre. The road distance comes from OpenStreetMap roads.