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Distance from Tianjin to Ouagadougou

Straight line

11,493 km
7,141 mi · 6,206 NM

By road

12,064 km
7,496 mi

Travel time

141 h 5 min
flight ≈ 14 h 52 min

Direction

WNW 298°
initial bearing

Open in the calculator (stops, directions, fuel cost) → Ouagadougou → Tianjin

How far is Tianjin from Ouagadougou?

Tianjin (China) and Ouagadougou (Burkina Faso) are very far apart: 11,493 km in a straight line, that is 7,141 miles or 6,206 nautical miles. The distance is measured over the Earth's surface (WGS84 ellipsoid) along the shortest possible path.

By road, Tianjin to Ouagadougou is 12,064 km (7,496 miles), about 141 h 5 min by car on the fastest route, without traffic or stops. The road is 5% longer than the straight line.

From Tianjin, Ouagadougou lies to the north-west (initial bearing 298°). The route crosses from China into Burkina Faso. The halfway point is at 42.8975°, 46.8526°.

A direct flight would take about 14 h 52 min (800 km/h cruise plus take-off and landing). The road distance and driving time are calculated on the map from OpenStreetMap roads.

Frequently asked questions

How far is Tianjin from Ouagadougou?

By road it is 12,064 km (7,496 miles) from Tianjin to Ouagadougou; in a straight line it is 11,493 km (7,141 miles).

How long is the drive from Tianjin to Ouagadougou?

About 141 h 5 min on the fastest route (12,064 km), without traffic or stops.

In which direction is Ouagadougou from Tianjin?

Ouagadougou is to the north-west of Tianjin, at an initial bearing of 298°.

How long is the flight from Tianjin to Ouagadougou?

A direct flight would take about 14 h 52 min at an average cruising speed of 800 km/h.

How is the distance calculated?

The straight-line distance is computed on the WGS84 ellipsoid with the Vincenty formula, accurate to the metre. The road distance comes from OpenStreetMap roads.