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Distance from Ouagadougou to Tianjin

Straight line

11,493 km
7,141 mi · 6,206 NM

By road

12,080 km
7,506 mi

Travel time

141 h 8 min
flight ≈ 14 h 52 min

Direction

NE 44°
initial bearing

Open in the calculator (stops, directions, fuel cost) → Tianjin → Ouagadougou

How far is Ouagadougou from Tianjin?

Ouagadougou (Burkina Faso) and Tianjin (China) are very far apart: 11,493 km in a straight line, that is 7,141 miles or 6,206 nautical miles. The distance is measured over the Earth's surface (WGS84 ellipsoid) along the shortest possible path.

By road, Ouagadougou to Tianjin is 12,080 km (7,506 miles), about 141 h 8 min by car on the fastest route, without traffic or stops. The road is 5% longer than the straight line.

From Ouagadougou, Tianjin lies to the north-east (initial bearing 44°). The route crosses from Burkina Faso into China. The halfway point is at 42.8975°, 46.8526°.

A direct flight would take about 14 h 52 min (800 km/h cruise plus take-off and landing). The road distance and driving time are calculated on the map from OpenStreetMap roads.

Frequently asked questions

How far is Ouagadougou from Tianjin?

By road it is 12,080 km (7,506 miles) from Ouagadougou to Tianjin; in a straight line it is 11,493 km (7,141 miles).

How long is the drive from Ouagadougou to Tianjin?

About 141 h 8 min on the fastest route (12,080 km), without traffic or stops.

In which direction is Tianjin from Ouagadougou?

Tianjin is to the north-east of Ouagadougou, at an initial bearing of 44°.

How long is the flight from Ouagadougou to Tianjin?

A direct flight would take about 14 h 52 min at an average cruising speed of 800 km/h.

How is the distance calculated?

The straight-line distance is computed on the WGS84 ellipsoid with the Vincenty formula, accurate to the metre. The road distance comes from OpenStreetMap roads.