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Distance from The Bronx to Puebla

Straight line

3,348 km
2,081 mi · 1,808 NM

By road

…
calculating

Travel time

…
flight ≈ 4 h 41 min

Direction

SW 231°
initial bearing

Open in the calculator (stops, directions, fuel cost) → Puebla → The Bronx

How far is The Bronx from Puebla?

The Bronx (United States) and Puebla (Mexico) are very far apart: 3,348 km in a straight line, that is 2,081 miles or 1,808 nautical miles. The distance is measured over the Earth's surface (WGS84 ellipsoid) along the shortest possible path.

From The Bronx, Puebla lies to the south-west (initial bearing 231°). The route crosses from United States into Mexico. The halfway point is at 30.5031°, -87.4059°.

A direct flight would take about 4 h 41 min (800 km/h cruise plus take-off and landing). The road distance and driving time are calculated on the map from OpenStreetMap roads.

Frequently asked questions

How far is The Bronx from Puebla?

The straight-line distance between The Bronx and Puebla is 3,348 km (2,081 miles). The road distance is longer and is calculated on the map.

In which direction is Puebla from The Bronx?

Puebla is to the south-west of The Bronx, at an initial bearing of 231°.

How long is the flight from The Bronx to Puebla?

A direct flight would take about 4 h 41 min at an average cruising speed of 800 km/h.

How is the distance calculated?

The straight-line distance is computed on the WGS84 ellipsoid with the Vincenty formula, accurate to the metre. The road distance comes from OpenStreetMap roads.