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Distance from Puebla to The Bronx

Straight line

3,348 km
2,081 mi · 1,808 NM

By road

4,105 km
2,551 mi

Travel time

49 h 54 min
flight ≈ 4 h 41 min

Direction

NE 38°
initial bearing

Open in the calculator (stops, directions, fuel cost) → The Bronx → Puebla

How far is Puebla from The Bronx?

Puebla (Mexico) and The Bronx (United States) are very far apart: 3,348 km in a straight line, that is 2,081 miles or 1,808 nautical miles. The distance is measured over the Earth's surface (WGS84 ellipsoid) along the shortest possible path.

By road, Puebla to The Bronx is 4,105 km (2,551 miles), about 49 h 54 min by car on the fastest route, without traffic or stops. The road is 23% longer than the straight line.

From Puebla, The Bronx lies to the north-east (initial bearing 38°). The route crosses from Mexico into United States. The halfway point is at 30.5031°, -87.4059°.

A direct flight would take about 4 h 41 min (800 km/h cruise plus take-off and landing). The road distance and driving time are calculated on the map from OpenStreetMap roads.

Frequently asked questions

How far is Puebla from The Bronx?

By road it is 4,105 km (2,551 miles) from Puebla to The Bronx; in a straight line it is 3,348 km (2,081 miles).

How long is the drive from Puebla to The Bronx?

About 49 h 54 min on the fastest route (4,105 km), without traffic or stops.

In which direction is The Bronx from Puebla?

The Bronx is to the north-east of Puebla, at an initial bearing of 38°.

How long is the flight from Puebla to The Bronx?

A direct flight would take about 4 h 41 min at an average cruising speed of 800 km/h.

How is the distance calculated?

The straight-line distance is computed on the WGS84 ellipsoid with the Vincenty formula, accurate to the metre. The road distance comes from OpenStreetMap roads.