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Distance from Sevastopol to Kremenchuk

Straight line

496 km
308 mi · 268 NM

By road

850 km
528 mi

Travel time

14 h 2 min
flight ≈ 1 h 7 min

Direction

N 359°
initial bearing

Open in the calculator (stops, directions, fuel cost) → Kremenchuk → Sevastopol

How far is Sevastopol from Kremenchuk?

Sevastopol (Ukraine) and Kremenchuk (Ukraine) are a medium distance apart: 496 km in a straight line, that is 308 miles or 268 nautical miles. The distance is measured over the Earth's surface (WGS84 ellipsoid) along the shortest possible path.

By road, Sevastopol to Kremenchuk is 850 km (528 miles), about 14 h 2 min by car on the fastest route, without traffic or stops. The road is 71% longer than the straight line.

From Sevastopol, Kremenchuk lies to the north (initial bearing 359°). Both cities are in Ukraine. The halfway point is at 46.8380°, 33.4730°.

A direct flight would take about 1 h 7 min (800 km/h cruise plus take-off and landing). The road distance and driving time are calculated on the map from OpenStreetMap roads.

Frequently asked questions

How far is Sevastopol from Kremenchuk?

By road it is 850 km (528 miles) from Sevastopol to Kremenchuk; in a straight line it is 496 km (308 miles).

How long is the drive from Sevastopol to Kremenchuk?

About 14 h 2 min on the fastest route (850 km), without traffic or stops.

In which direction is Kremenchuk from Sevastopol?

Kremenchuk is to the north of Sevastopol, at an initial bearing of 359°.

How long is the flight from Sevastopol to Kremenchuk?

A direct flight would take about 1 h 7 min at an average cruising speed of 800 km/h.

How is the distance calculated?

The straight-line distance is computed on the WGS84 ellipsoid with the Vincenty formula, accurate to the metre. The road distance comes from OpenStreetMap roads.