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Distance from Kremenchuk to Sevastopol

Straight line

496 km
308 mi · 268 NM

By road

851 km
528 mi

Travel time

13 h 57 min
flight ≈ 1 h 7 min

Direction

S 179°
initial bearing

Open in the calculator (stops, directions, fuel cost) → Sevastopol → Kremenchuk

How far is Kremenchuk from Sevastopol?

Kremenchuk (Ukraine) and Sevastopol (Ukraine) are a medium distance apart: 496 km in a straight line, that is 308 miles or 268 nautical miles. The distance is measured over the Earth's surface (WGS84 ellipsoid) along the shortest possible path.

By road, Kremenchuk to Sevastopol is 851 km (528 miles), about 13 h 57 min by car on the fastest route, without traffic or stops. The road is 72% longer than the straight line.

From Kremenchuk, Sevastopol lies to the south (initial bearing 179°). Both cities are in Ukraine. The halfway point is at 46.8380°, 33.4730°.

A direct flight would take about 1 h 7 min (800 km/h cruise plus take-off and landing). The road distance and driving time are calculated on the map from OpenStreetMap roads.

Frequently asked questions

How far is Kremenchuk from Sevastopol?

By road it is 851 km (528 miles) from Kremenchuk to Sevastopol; in a straight line it is 496 km (308 miles).

How long is the drive from Kremenchuk to Sevastopol?

About 13 h 57 min on the fastest route (851 km), without traffic or stops.

In which direction is Sevastopol from Kremenchuk?

Sevastopol is to the south of Kremenchuk, at an initial bearing of 179°.

How long is the flight from Kremenchuk to Sevastopol?

A direct flight would take about 1 h 7 min at an average cruising speed of 800 km/h.

How is the distance calculated?

The straight-line distance is computed on the WGS84 ellipsoid with the Vincenty formula, accurate to the metre. The road distance comes from OpenStreetMap roads.