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Distance from Sevastopol to Harbin

Straight line

6,867 km
4,267 mi · 3,708 NM

By road

…
calculating

Travel time

…
flight ≈ 9 h 5 min

Direction

NE 52°
initial bearing

Open in the calculator (stops, directions, fuel cost) → Harbin → Sevastopol

How far is Sevastopol from Harbin?

Sevastopol (Ukraine) and Harbin (China) are very far apart: 6,867 km in a straight line, that is 4,267 miles or 3,708 nautical miles. The distance is measured over the Earth's surface (WGS84 ellipsoid) along the shortest possible path.

From Sevastopol, Harbin lies to the north-east (initial bearing 52°). The route crosses from Ukraine into China. The halfway point is at 55.6554°, 79.4788°.

A direct flight would take about 9 h 5 min (800 km/h cruise plus take-off and landing). The road distance and driving time are calculated on the map from OpenStreetMap roads.

Frequently asked questions

How far is Sevastopol from Harbin?

The straight-line distance between Sevastopol and Harbin is 6,867 km (4,267 miles). The road distance is longer and is calculated on the map.

In which direction is Harbin from Sevastopol?

Harbin is to the north-east of Sevastopol, at an initial bearing of 52°.

How long is the flight from Sevastopol to Harbin?

A direct flight would take about 9 h 5 min at an average cruising speed of 800 km/h.

How is the distance calculated?

The straight-line distance is computed on the WGS84 ellipsoid with the Vincenty formula, accurate to the metre. The road distance comes from OpenStreetMap roads.