EN RO

Distance from Harbin to Sevastopol

Straight line

6,867 km
4,267 mi · 3,708 NM

By road

9,326 km
5,795 mi

Travel time

114 h 3 min
flight ≈ 9 h 5 min

Direction

NW 306°
initial bearing

Open in the calculator (stops, directions, fuel cost) → Sevastopol → Harbin

How far is Harbin from Sevastopol?

Harbin (China) and Sevastopol (Ukraine) are very far apart: 6,867 km in a straight line, that is 4,267 miles or 3,708 nautical miles. The distance is measured over the Earth's surface (WGS84 ellipsoid) along the shortest possible path.

By road, Harbin to Sevastopol is 9,326 km (5,795 miles), about 114 h 3 min by car on the fastest route, without traffic or stops. The road is 36% longer than the straight line.

From Harbin, Sevastopol lies to the north-west (initial bearing 306°). The route crosses from China into Ukraine. The halfway point is at 55.6554°, 79.4788°.

A direct flight would take about 9 h 5 min (800 km/h cruise plus take-off and landing). The road distance and driving time are calculated on the map from OpenStreetMap roads.

Frequently asked questions

How far is Harbin from Sevastopol?

By road it is 9,326 km (5,795 miles) from Harbin to Sevastopol; in a straight line it is 6,867 km (4,267 miles).

How long is the drive from Harbin to Sevastopol?

About 114 h 3 min on the fastest route (9,326 km), without traffic or stops.

In which direction is Sevastopol from Harbin?

Sevastopol is to the north-west of Harbin, at an initial bearing of 306°.

How long is the flight from Harbin to Sevastopol?

A direct flight would take about 9 h 5 min at an average cruising speed of 800 km/h.

How is the distance calculated?

The straight-line distance is computed on the WGS84 ellipsoid with the Vincenty formula, accurate to the metre. The road distance comes from OpenStreetMap roads.