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Distance from Sevastopol to Dnipro

Straight line

444 km
276 mi · 240 NM

By road

690 km
429 mi

Travel time

11 h 30 min
flight ≈ 1 h 3 min

Direction

NNE 15°
initial bearing

Open in the calculator (stops, directions, fuel cost) → Dnipro → Sevastopol

How far is Sevastopol from Dnipro?

Sevastopol (Ukraine) and Dnipro (Ukraine) are a medium distance apart: 444 km in a straight line, that is 276 miles or 240 nautical miles. The distance is measured over the Earth's surface (WGS84 ellipsoid) along the shortest possible path.

By road, Sevastopol to Dnipro is 690 km (429 miles), about 11 h 30 min by car on the fastest route, without traffic or stops. The road is 56% longer than the straight line.

From Sevastopol, Dnipro lies to the north (initial bearing 15°). Both cities are in Ukraine. The halfway point is at 46.5361°, 34.2531°.

A direct flight would take about 1 h 3 min (800 km/h cruise plus take-off and landing). The road distance and driving time are calculated on the map from OpenStreetMap roads.

Frequently asked questions

How far is Sevastopol from Dnipro?

By road it is 690 km (429 miles) from Sevastopol to Dnipro; in a straight line it is 444 km (276 miles).

How long is the drive from Sevastopol to Dnipro?

About 11 h 30 min on the fastest route (690 km), without traffic or stops.

In which direction is Dnipro from Sevastopol?

Dnipro is to the north of Sevastopol, at an initial bearing of 15°.

How long is the flight from Sevastopol to Dnipro?

A direct flight would take about 1 h 3 min at an average cruising speed of 800 km/h.

How is the distance calculated?

The straight-line distance is computed on the WGS84 ellipsoid with the Vincenty formula, accurate to the metre. The road distance comes from OpenStreetMap roads.