EN RO

Distance from Dnipro to Sevastopol

Straight line

444 km
276 mi · 240 NM

By road

690 km
429 mi

Travel time

11 h 25 min
flight ≈ 1 h 3 min

Direction

SSW 196°
initial bearing

Open in the calculator (stops, directions, fuel cost) → Sevastopol → Dnipro

How far is Dnipro from Sevastopol?

Dnipro (Ukraine) and Sevastopol (Ukraine) are a medium distance apart: 444 km in a straight line, that is 276 miles or 240 nautical miles. The distance is measured over the Earth's surface (WGS84 ellipsoid) along the shortest possible path.

By road, Dnipro to Sevastopol is 690 km (429 miles), about 11 h 25 min by car on the fastest route, without traffic or stops. The road is 56% longer than the straight line.

From Dnipro, Sevastopol lies to the south (initial bearing 196°). Both cities are in Ukraine. The halfway point is at 46.5361°, 34.2531°.

A direct flight would take about 1 h 3 min (800 km/h cruise plus take-off and landing). The road distance and driving time are calculated on the map from OpenStreetMap roads.

Frequently asked questions

How far is Dnipro from Sevastopol?

By road it is 690 km (429 miles) from Dnipro to Sevastopol; in a straight line it is 444 km (276 miles).

How long is the drive from Dnipro to Sevastopol?

About 11 h 25 min on the fastest route (690 km), without traffic or stops.

In which direction is Sevastopol from Dnipro?

Sevastopol is to the south of Dnipro, at an initial bearing of 196°.

How long is the flight from Dnipro to Sevastopol?

A direct flight would take about 1 h 3 min at an average cruising speed of 800 km/h.

How is the distance calculated?

The straight-line distance is computed on the WGS84 ellipsoid with the Vincenty formula, accurate to the metre. The road distance comes from OpenStreetMap roads.