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Distance from Sevastopol to Chernihiv

Straight line

785 km
488 mi · 424 NM

By road

1,274 km
792 mi

Travel time

19 h 14 min
flight ≈ 1 h 29 min

Direction

NNW 349°
initial bearing

Open in the calculator (stops, directions, fuel cost) → Chernihiv → Sevastopol

How far is Sevastopol from Chernihiv?

Sevastopol (Ukraine) and Chernihiv (Ukraine) are quite far apart: 785 km in a straight line, that is 488 miles or 424 nautical miles. The distance is measured over the Earth's surface (WGS84 ellipsoid) along the shortest possible path.

By road, Sevastopol to Chernihiv is 1,274 km (792 miles), about 19 h 14 min by car on the fastest route, without traffic or stops. The road is 62% longer than the straight line.

From Sevastopol, Chernihiv lies to the north (initial bearing 349°). Both cities are in Ukraine. The halfway point is at 48.0621°, 32.4781°.

A direct flight would take about 1 h 29 min (800 km/h cruise plus take-off and landing). The road distance and driving time are calculated on the map from OpenStreetMap roads.

Frequently asked questions

How far is Sevastopol from Chernihiv?

By road it is 1,274 km (792 miles) from Sevastopol to Chernihiv; in a straight line it is 785 km (488 miles).

How long is the drive from Sevastopol to Chernihiv?

About 19 h 14 min on the fastest route (1,274 km), without traffic or stops.

In which direction is Chernihiv from Sevastopol?

Chernihiv is to the north of Sevastopol, at an initial bearing of 349°.

How long is the flight from Sevastopol to Chernihiv?

A direct flight would take about 1 h 29 min at an average cruising speed of 800 km/h.

How is the distance calculated?

The straight-line distance is computed on the WGS84 ellipsoid with the Vincenty formula, accurate to the metre. The road distance comes from OpenStreetMap roads.