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Distance from Chernihiv to Sevastopol

Straight line

785 km
488 mi · 424 NM

By road

…
calculating

Travel time

…
flight ≈ 1 h 29 min

Direction

SSE 167°
initial bearing

Open in the calculator (stops, directions, fuel cost) → Sevastopol → Chernihiv

How far is Chernihiv from Sevastopol?

Chernihiv (Ukraine) and Sevastopol (Ukraine) are quite far apart: 785 km in a straight line, that is 488 miles or 424 nautical miles. The distance is measured over the Earth's surface (WGS84 ellipsoid) along the shortest possible path.

From Chernihiv, Sevastopol lies to the south (initial bearing 167°). Both cities are in Ukraine. The halfway point is at 48.0621°, 32.4781°.

A direct flight would take about 1 h 29 min (800 km/h cruise plus take-off and landing). The road distance and driving time are calculated on the map from OpenStreetMap roads.

Frequently asked questions

How far is Chernihiv from Sevastopol?

The straight-line distance between Chernihiv and Sevastopol is 785 km (488 miles). The road distance is longer and is calculated on the map.

In which direction is Sevastopol from Chernihiv?

Sevastopol is to the south of Chernihiv, at an initial bearing of 167°.

How long is the flight from Chernihiv to Sevastopol?

A direct flight would take about 1 h 29 min at an average cruising speed of 800 km/h.

How is the distance calculated?

The straight-line distance is computed on the WGS84 ellipsoid with the Vincenty formula, accurate to the metre. The road distance comes from OpenStreetMap roads.