EN RO

Distance from Zhytomyr to Sevastopol

Straight line

727 km
452 mi · 393 NM

By road

…
calculating

Travel time

…
flight ≈ 1 h 25 min

Direction

SSE 148°
initial bearing

Open in the calculator (stops, directions, fuel cost) → Sevastopol → Zhytomyr

How far is Zhytomyr from Sevastopol?

Zhytomyr (Ukraine) and Sevastopol (Ukraine) are quite far apart: 727 km in a straight line, that is 452 miles or 393 nautical miles. The distance is measured over the Earth's surface (WGS84 ellipsoid) along the shortest possible path.

From Zhytomyr, Sevastopol lies to the south-east (initial bearing 148°). Both cities are in Ukraine. The halfway point is at 47.4619°, 31.2294°.

A direct flight would take about 1 h 25 min (800 km/h cruise plus take-off and landing). The road distance and driving time are calculated on the map from OpenStreetMap roads.

Frequently asked questions

How far is Zhytomyr from Sevastopol?

The straight-line distance between Zhytomyr and Sevastopol is 727 km (452 miles). The road distance is longer and is calculated on the map.

In which direction is Sevastopol from Zhytomyr?

Sevastopol is to the south-east of Zhytomyr, at an initial bearing of 148°.

How long is the flight from Zhytomyr to Sevastopol?

A direct flight would take about 1 h 25 min at an average cruising speed of 800 km/h.

How is the distance calculated?

The straight-line distance is computed on the WGS84 ellipsoid with the Vincenty formula, accurate to the metre. The road distance comes from OpenStreetMap roads.