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Distance from Wuhan to Sevastopol

Straight line

7,007 km
4,354 mi · 3,783 NM

By road

8,829 km
5,486 mi

Travel time

107 h 18 min
flight ≈ 9 h 16 min

Direction

NW 308°
initial bearing

Open in the calculator (stops, directions, fuel cost) → Sevastopol → Wuhan

How far is Wuhan from Sevastopol?

Wuhan (China) and Sevastopol (Ukraine) are very far apart: 7,007 km in a straight line, that is 4,354 miles or 3,783 nautical miles. The distance is measured over the Earth's surface (WGS84 ellipsoid) along the shortest possible path.

By road, Wuhan to Sevastopol is 8,829 km (5,486 miles), about 107 h 18 min by car on the fastest route, without traffic or stops. The road is 26% longer than the straight line.

From Wuhan, Sevastopol lies to the north-west (initial bearing 308°). The route crosses from China into Ukraine. The halfway point is at 45.2117°, 78.4979°.

A direct flight would take about 9 h 16 min (800 km/h cruise plus take-off and landing). The road distance and driving time are calculated on the map from OpenStreetMap roads.

Frequently asked questions

How far is Wuhan from Sevastopol?

By road it is 8,829 km (5,486 miles) from Wuhan to Sevastopol; in a straight line it is 7,007 km (4,354 miles).

How long is the drive from Wuhan to Sevastopol?

About 107 h 18 min on the fastest route (8,829 km), without traffic or stops.

In which direction is Sevastopol from Wuhan?

Sevastopol is to the north-west of Wuhan, at an initial bearing of 308°.

How long is the flight from Wuhan to Sevastopol?

A direct flight would take about 9 h 16 min at an average cruising speed of 800 km/h.

How is the distance calculated?

The straight-line distance is computed on the WGS84 ellipsoid with the Vincenty formula, accurate to the metre. The road distance comes from OpenStreetMap roads.