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Distance from Suzhou to Tiraspol

Straight line

7,615 km
4,732 mi · 4,112 NM

By road

9,542 km
5,929 mi

Travel time

117 h 46 min
flight ≈ 10 h 1 min

Direction

NW 313°
initial bearing

Open in the calculator (stops, directions, fuel cost) → Tiraspol → Suzhou

How far is Suzhou from Tiraspol?

Suzhou (China) and Tiraspol (Moldova) are very far apart: 7,615 km in a straight line, that is 4,732 miles or 4,112 nautical miles. The distance is measured over the Earth's surface (WGS84 ellipsoid) along the shortest possible path.

By road, Suzhou to Tiraspol is 9,542 km (5,929 miles), about 117 h 46 min by car on the fastest route, without traffic or stops. The road is 25% longer than the straight line.

From Suzhou, Tiraspol lies to the north-west (initial bearing 313°). The route crosses from China into Moldova. The halfway point is at 49.0091°, 81.5400°.

A direct flight would take about 10 h 1 min (800 km/h cruise plus take-off and landing). The road distance and driving time are calculated on the map from OpenStreetMap roads.

Frequently asked questions

How far is Suzhou from Tiraspol?

By road it is 9,542 km (5,929 miles) from Suzhou to Tiraspol; in a straight line it is 7,615 km (4,732 miles).

How long is the drive from Suzhou to Tiraspol?

About 117 h 46 min on the fastest route (9,542 km), without traffic or stops.

In which direction is Tiraspol from Suzhou?

Tiraspol is to the north-west of Suzhou, at an initial bearing of 313°.

How long is the flight from Suzhou to Tiraspol?

A direct flight would take about 10 h 1 min at an average cruising speed of 800 km/h.

How is the distance calculated?

The straight-line distance is computed on the WGS84 ellipsoid with the Vincenty formula, accurate to the metre. The road distance comes from OpenStreetMap roads.