EN RO

Distance from Pucioasa to Drobeta-Turnu Severin

Straight line

225 km
140 mi · 122 NM

By road

313 km
194 mi

Travel time

4 h 53 min
flight ≈ 47 min

Direction

WSW 258°
initial bearing

Open in the calculator (stops, directions, fuel cost) → Drobeta-Turnu Severin → Pucioasa

How far is Pucioasa from Drobeta-Turnu Severin?

Pucioasa (Romania) and Drobeta-Turnu Severin (Romania) are a medium distance apart: 225 km in a straight line, that is 140 miles or 122 nautical miles. The distance is measured over the Earth's surface (WGS84 ellipsoid) along the shortest possible path.

By road, Pucioasa to Drobeta-Turnu Severin is 313 km (194 miles), about 4 h 53 min by car on the fastest route, without traffic or stops. The road is 39% longer than the straight line.

From Pucioasa, Drobeta-Turnu Severin lies to the west (initial bearing 258°). Both cities are in Romania. The halfway point is at 44.8609°, 24.0372°.

A direct flight would take about 47 min (800 km/h cruise plus take-off and landing). The road distance and driving time are calculated on the map from OpenStreetMap roads.

Frequently asked questions

How far is Pucioasa from Drobeta-Turnu Severin?

By road it is 313 km (194 miles) from Pucioasa to Drobeta-Turnu Severin; in a straight line it is 225 km (140 miles).

How long is the drive from Pucioasa to Drobeta-Turnu Severin?

About 4 h 53 min on the fastest route (313 km), without traffic or stops.

In which direction is Drobeta-Turnu Severin from Pucioasa?

Drobeta-Turnu Severin is to the west of Pucioasa, at an initial bearing of 258°.

How long is the flight from Pucioasa to Drobeta-Turnu Severin?

A direct flight would take about 47 min at an average cruising speed of 800 km/h.

How is the distance calculated?

The straight-line distance is computed on the WGS84 ellipsoid with the Vincenty formula, accurate to the metre. The road distance comes from OpenStreetMap roads.