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Distance from Lima to Sevastopol

Straight line

12,567 km
7,809 mi · 6,786 NM

By road

5,465 km
3,396 mi

Travel time

64 h 36 min
flight ≈ 16 h 13 min

Direction

NE 46°
initial bearing

Open in the calculator (stops, directions, fuel cost) → Sevastopol → Lima

How far is Lima from Sevastopol?

Lima (Peru) and Sevastopol (Ukraine) are very far apart: 12,567 km in a straight line, that is 7,809 miles or 6,786 nautical miles. The distance is measured over the Earth's surface (WGS84 ellipsoid) along the shortest possible path.

By road, Lima to Sevastopol is 5,465 km (3,396 miles), about 64 h 36 min by car on the fastest route, without traffic or stops. The road follows the straight line closely.

From Lima, Sevastopol lies to the north-east (initial bearing 46°). The route crosses from Peru into Ukraine. The halfway point is at 26.5658°, -34.5516°.

A direct flight would take about 16 h 13 min (800 km/h cruise plus take-off and landing). The road distance and driving time are calculated on the map from OpenStreetMap roads.

Frequently asked questions

How far is Lima from Sevastopol?

By road it is 5,465 km (3,396 miles) from Lima to Sevastopol; in a straight line it is 12,567 km (7,809 miles).

How long is the drive from Lima to Sevastopol?

About 64 h 36 min on the fastest route (5,465 km), without traffic or stops.

In which direction is Sevastopol from Lima?

Sevastopol is to the north-east of Lima, at an initial bearing of 46°.

How long is the flight from Lima to Sevastopol?

A direct flight would take about 16 h 13 min at an average cruising speed of 800 km/h.

How is the distance calculated?

The straight-line distance is computed on the WGS84 ellipsoid with the Vincenty formula, accurate to the metre. The road distance comes from OpenStreetMap roads.