Distance from Lahore to Sevastopol
Straight line
By road
Travel time
Direction
Open in the calculator (stops, directions, fuel cost) → Sevastopol → Lahore
How far is Lahore from Sevastopol?
Lahore (Pakistan) and Sevastopol (Ukraine) are very far apart: 3,816 km in a straight line, that is 2,371 miles or 2,060 nautical miles. The distance is measured over the Earth's surface (WGS84 ellipsoid) along the shortest possible path.
From Lahore, Sevastopol lies to the north-west (initial bearing 304°). The route crosses from Pakistan into Ukraine. The halfway point is at 39.8845°, 55.8466°.
A direct flight would take about 5 h 16 min (800 km/h cruise plus take-off and landing). The road distance and driving time are calculated on the map from OpenStreetMap roads.
Other distances from Lahore
- Lahore – Amritsar 50 km
- Lahore – Gujranwala 68 km
- Lahore – Faisalabad 121 km
- Lahore – Ludhiāna 160 km
- Lahore – Rawalpindi 258 km
- Lahore – Gorakhpur 267 km
- Lahore – Multan 313 km
- Lahore – Peshawar 376 km
- Lahore – Najafgarh 414 km
Other distances from Sevastopol
- Sevastopol – Simferopol 61 km
- Sevastopol – Kherson 238 km
- Sevastopol – Mykolayiv 288 km
- Sevastopol – Odessa 301 km
- Sevastopol – Kryvyi Rih 367 km
- Sevastopol – Tulcea 377 km
- Sevastopol – Zaporizhia 380 km
- Sevastopol – Babadag 381 km
- Sevastopol – Tiraspol 391 km
Frequently asked questions
How far is Lahore from Sevastopol?
The straight-line distance between Lahore and Sevastopol is 3,816 km (2,371 miles). The road distance is longer and is calculated on the map.
In which direction is Sevastopol from Lahore?
Sevastopol is to the north-west of Lahore, at an initial bearing of 304°.
How long is the flight from Lahore to Sevastopol?
A direct flight would take about 5 h 16 min at an average cruising speed of 800 km/h.
How is the distance calculated?
The straight-line distance is computed on the WGS84 ellipsoid with the Vincenty formula, accurate to the metre. The road distance comes from OpenStreetMap roads.