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Distance from Lahore to Sebeș

Straight line

4,606 km
2,862 mi · 2,487 NM

By road

6,290 km
3,909 mi

Travel time

78 h 18 min
flight ≈ 6 h 15 min

Direction

NW 305°
initial bearing

Open in the calculator (stops, directions, fuel cost) → Sebeș → Lahore

How far is Lahore from Sebeș?

Lahore (Pakistan) and Sebeș (Romania) are very far apart: 4,606 km in a straight line, that is 2,862 miles or 2,487 nautical miles. The distance is measured over the Earth's surface (WGS84 ellipsoid) along the shortest possible path.

By road, Lahore to Sebeș is 6,290 km (3,909 miles), about 78 h 18 min by car on the fastest route, without traffic or stops. The road is 37% longer than the straight line.

From Lahore, Sebeș lies to the north-west (initial bearing 305°). The route crosses from Pakistan into Romania. The halfway point is at 41.5921°, 51.7163°.

A direct flight would take about 6 h 15 min (800 km/h cruise plus take-off and landing). The road distance and driving time are calculated on the map from OpenStreetMap roads.

Frequently asked questions

How far is Lahore from Sebeș?

By road it is 6,290 km (3,909 miles) from Lahore to Sebeș; in a straight line it is 4,606 km (2,862 miles).

How long is the drive from Lahore to Sebeș?

About 78 h 18 min on the fastest route (6,290 km), without traffic or stops.

In which direction is Sebeș from Lahore?

Sebeș is to the north-west of Lahore, at an initial bearing of 305°.

How long is the flight from Lahore to Sebeș?

A direct flight would take about 6 h 15 min at an average cruising speed of 800 km/h.

How is the distance calculated?

The straight-line distance is computed on the WGS84 ellipsoid with the Vincenty formula, accurate to the metre. The road distance comes from OpenStreetMap roads.