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Distance from Khmelnytskyi to Sevastopol

Straight line

729 km
453 mi · 394 NM

By road

1,376 km
855 mi

Travel time

22 h 20 min
flight ≈ 1 h 25 min

Direction

SE 135°
initial bearing

Open in the calculator (stops, directions, fuel cost) → Sevastopol → Khmelnytskyi

How far is Khmelnytskyi from Sevastopol?

Khmelnytskyi (Ukraine) and Sevastopol (Ukraine) are quite far apart: 729 km in a straight line, that is 453 miles or 394 nautical miles. The distance is measured over the Earth's surface (WGS84 ellipsoid) along the shortest possible path.

By road, Khmelnytskyi to Sevastopol is 1,376 km (855 miles), about 22 h 20 min by car on the fastest route, without traffic or stops. The road is 89% longer than the straight line.

From Khmelnytskyi, Sevastopol lies to the south-east (initial bearing 135°). Both cities are in Ukraine. The halfway point is at 47.0610°, 30.4062°.

A direct flight would take about 1 h 25 min (800 km/h cruise plus take-off and landing). The road distance and driving time are calculated on the map from OpenStreetMap roads.

Frequently asked questions

How far is Khmelnytskyi from Sevastopol?

By road it is 1,376 km (855 miles) from Khmelnytskyi to Sevastopol; in a straight line it is 729 km (453 miles).

How long is the drive from Khmelnytskyi to Sevastopol?

About 22 h 20 min on the fastest route (1,376 km), without traffic or stops.

In which direction is Sevastopol from Khmelnytskyi?

Sevastopol is to the south-east of Khmelnytskyi, at an initial bearing of 135°.

How long is the flight from Khmelnytskyi to Sevastopol?

A direct flight would take about 1 h 25 min at an average cruising speed of 800 km/h.

How is the distance calculated?

The straight-line distance is computed on the WGS84 ellipsoid with the Vincenty formula, accurate to the metre. The road distance comes from OpenStreetMap roads.