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Distance from Chengdu to Sevastopol

Straight line

6,217 km
3,863 mi · 3,357 NM

By road

8,112 km
5,040 mi

Travel time

100 h 35 min
flight ≈ 8 h 16 min

Direction

NW 306°
initial bearing

Open in the calculator (stops, directions, fuel cost) → Sevastopol → Chengdu

How far is Chengdu from Sevastopol?

Chengdu (China) and Sevastopol (Ukraine) are very far apart: 6,217 km in a straight line, that is 3,863 miles or 3,357 nautical miles. The distance is measured over the Earth's surface (WGS84 ellipsoid) along the shortest possible path.

By road, Chengdu to Sevastopol is 8,112 km (5,040 miles), about 100 h 35 min by car on the fastest route, without traffic or stops. The road is 30% longer than the straight line.

From Chengdu, Sevastopol lies to the north-west (initial bearing 306°). The route crosses from China into Ukraine. The halfway point is at 43.3031°, 72.6093°.

A direct flight would take about 8 h 16 min (800 km/h cruise plus take-off and landing). The road distance and driving time are calculated on the map from OpenStreetMap roads.

Frequently asked questions

How far is Chengdu from Sevastopol?

By road it is 8,112 km (5,040 miles) from Chengdu to Sevastopol; in a straight line it is 6,217 km (3,863 miles).

How long is the drive from Chengdu to Sevastopol?

About 100 h 35 min on the fastest route (8,112 km), without traffic or stops.

In which direction is Sevastopol from Chengdu?

Sevastopol is to the north-west of Chengdu, at an initial bearing of 306°.

How long is the flight from Chengdu to Sevastopol?

A direct flight would take about 8 h 16 min at an average cruising speed of 800 km/h.

How is the distance calculated?

The straight-line distance is computed on the WGS84 ellipsoid with the Vincenty formula, accurate to the metre. The road distance comes from OpenStreetMap roads.