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Distance from Bogotá to Sebeș

Straight line

10,234 km
6,359 mi · 5,526 NM

By road

3,707 km
2,303 mi

Travel time

39 h 7 min
flight ≈ 13 h 18 min

Direction

NE 44°
initial bearing

Open in the calculator (stops, directions, fuel cost) → Sebeș → Bogotá

How far is Bogotá from Sebeș?

Bogotá (Colombia) and Sebeș (Romania) are very far apart: 10,234 km in a straight line, that is 6,359 miles or 5,526 nautical miles. The distance is measured over the Earth's surface (WGS84 ellipsoid) along the shortest possible path.

By road, Bogotá to Sebeș is 3,707 km (2,303 miles), about 39 h 7 min by car on the fastest route, without traffic or stops. The road follows the straight line closely.

From Bogotá, Sebeș lies to the north-east (initial bearing 44°). The route crosses from Colombia into Romania. The halfway point is at 35.1078°, -36.7734°.

A direct flight would take about 13 h 18 min (800 km/h cruise plus take-off and landing). The road distance and driving time are calculated on the map from OpenStreetMap roads.

Frequently asked questions

How far is Bogotá from Sebeș?

By road it is 3,707 km (2,303 miles) from Bogotá to Sebeș; in a straight line it is 10,234 km (6,359 miles).

How long is the drive from Bogotá to Sebeș?

About 39 h 7 min on the fastest route (3,707 km), without traffic or stops.

In which direction is Sebeș from Bogotá?

Sebeș is to the north-east of Bogotá, at an initial bearing of 44°.

How long is the flight from Bogotá to Sebeș?

A direct flight would take about 13 h 18 min at an average cruising speed of 800 km/h.

How is the distance calculated?

The straight-line distance is computed on the WGS84 ellipsoid with the Vincenty formula, accurate to the metre. The road distance comes from OpenStreetMap roads.